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Hausdorff maximal principle

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In mathematics, the Hausdorff maximal principle is an alternate and earlier formulation of Zorn's lemma proved by Felix Hausdorff in 1914 (Moore 1982:168). It states that in any partially ordered set, every totally ordered subset is contained in a maximal totally ordered subset.

In a partially ordered set, a totally ordered subset is also called a chain. Thus, the maximal principle says every chain in the set extends to a maximal chain.

The Hausdorff maximal principle is one of many statements equivalent to the axiom of choice over ZF (Zermelo–Fraenkel set theory without the axiom of choice). The principle is also called the Hausdorff maximality theorem or the Kuratowski lemma (Kelley 1955:33).

Statement

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The Hausdorff maximal principle states that, in any partially ordered set, every totally ordered subset is contained in a maximal totally ordered subset (a totally ordered subset that, if enlarged in any way, does not remain totally ordered). In general, there may be many maximal totally ordered subsets containing a given totally ordered subset.

An equivalent form of the Hausdorff maximal principle is that in every partially ordered set there exists a maximal totally ordered subset. To prove that this statement follows from the original form, let A be a partially ordered set. Then is a totally ordered subset of A, hence there exists a maximal totally ordered subset containing , hence in particular A contains a maximal totally ordered subset. For the converse direction, let A be a partially ordered set and T a totally ordered subset of A. Then

is partially ordered by set inclusion , therefore it contains a maximal totally ordered subset P. Then the set satisfies the desired properties.

The proof that the Hausdorff maximal principle is equivalent to Zorn's lemma is very similar to this proof.[clarification needed]

Examples

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If A is any collection of sets, the relation "is a proper subset of" is a strict partial order on A. Suppose that A is the collection of all circular regions (interiors of circles) in the plane. One maximal totally ordered sub-collection of A consists of all circular regions with centers at the origin. Another maximal totally ordered sub-collection consists of all circular regions bounded by circles tangent from the right to the y-axis at the origin.

If (x0, y0) and (x1, y1) are two points of the plane , define (x0, y0) < (x1, y1) if y0 = y1 and x0 < x1. This is a partial ordering of under which two points are comparable only if they lie on the same horizontal line. The maximal totally ordered sets are horizontal lines in .

Application

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By the Hausdorff maximal principle, we can show every Hilbert space contains a maximal orthonormal subset as follows.[1] (This fact can be stated as saying that as Hilbert spaces.)

Let be the set of all orthonormal subsets of the given Hilbert space , which is partially ordered by set inclusion. It is nonempty as it contains the empty set and thus by the maximal principle, it contains a maximal chain . Let be the union of . We shall show it is a maximal orthonormal subset. First, if are in , then either or . That is, any given two distinct elements in are contained in some in and so they are orthogonal to each other (and of course, is a subset of the unit sphere in ). Second, if for some in , then cannot be in and so is a chain strictly larger than , a contradiction.

For the purpose of comparison, here is a proof of the same fact by Zorn's lemma. As above, let be the set of all orthonormal subsets of . If is a chain in , then the union of is also orthonormal by the same argument as above and so is an upper bound of . Thus, by Zorn's lemma, contains a maximal element . (So, the difference is that the maximal principle gives a maximal chain while Zorn's lemma gives a maximal element directly.)

Proof sketch

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The idea of the following proof is essentially due to Zermelo.[2][3] The same idea of the proof (namely, a tower) can also be used to show Zorn's lemma.

By the axiom of choice, we have a function such that for the power set of .

Let be the set of all chains (totally ordered subsets) in . For each , let be the set of all such that is a chain; i.e., is in . If , then let . Otherwise, let

Note is a maximal chain if and only if . Thus, we are done if we can find a chain such that .

Fix a chain in (for example, the empty set). We call a subset a tower over if

  1. is in .
  2. The union of each totally ordered subset is in , where "totally ordered" is with respect to set inclusion.
  3. For each in , is in .

There exists at least one tower over ; indeed, the set of all chains in containing is such a tower. Let be the intersection of all towers over , which is again a tower over . Then, with some work,[4] one sees is totally ordered with respect to set inclusion. Let be the union of . By 2., is in and then by 3., is in . Since is the union of , and thus ; i.e., a maximal chain exists. Also, if we take to be a given chain, then we get a maximal chain containing it.

References

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  1. ^ Rudin 1986, Theorem 4.22.
  2. ^ Halmos 1960, § 16.
  3. ^ Rudin 1986, Appendix
  4. ^ Editorial note: we should give a detail of this step.
  • Paul Halmos, Naive set theory. Princeton, NJ: D. Van Nostrand Company, 1960. Reprinted by Springer-Verlag, New York, 1974. ISBN 0-387-90092-6 (Springer-Verlag edition).
  • John Kelley (1955), General topology, Von Nostrand.
  • Gregory Moore (1982), Zermelo's axiom of choice, Springer.
  • James Munkres (2000), Topology, Pearson.
  • Appendix of Rudin, Walter (1986). Real and Complex Analysis (International Series in Pure and Applied Mathematics). McGraw-Hill. ISBN 978-0-07-054234-1.